QUESTION NO: 1 TestKing is migrating to an IPv6 addressing scheme. Identify the four valid IPv6 addresses below that could be used in this network. (Choose four) A. B. C. D. E. F. ::192:168:0:1 2002:c0a8:101::42 2000:: :: 2001:3452:4952:2837:: 2003:dead:beef:4dad:23:46:bb:101
Answer: A, B, D, F Explanation: From RFC 1884: IP Version 6 Addressing Architecture There are three conventional forms for representing IPv6 addresses as text strings: 1. The preferred form is x:x:x:x:x:x:x:x, where the 'x's are the hexadecimal values of the eight 16-bit pieces of the address. Examples: FEDC:BA98:7654:3210:FEDC:BA98:7654:3210 1080:0:0:0:8:800:200C:417A Note that it is not necessary to write the leading zeros in an individual field, but there must be at least one numeral in every field (except for the case described in 2.). 2. Due to the method of allocating certain styles of IPv6 addresses, it will be common for addresses to contain long strings of zero bits. In order to make writing addresses containing zero bits easier a special syntax is available to compress the zeros. The use of "::" indicates multiple groups of 16-bits of zeros. The "::" can only appear once in an address. The "::" can also be used to compress the leading and/or trailing zeros in an address. For example the following addresses: 1080:0:0:0:8:800:200C:417A a unicast address FF01:0:0:0:0:0:0:43 a multicast address 0:0:0:0:0:0:0:1 the loopback address 0:0:0:0:0:0:0:0 the unspecified addresses may be represented as: 1080::8:800:200C:417A a unicast address FF01::43 a multicast address ::1 the loopback address :: the unspecified addresses 3. An alternative form that is sometimes more convenient when dealing with a mixed environment of IPv4 and IPv6 nodes is x:x:x:x:x:x:d.d.d.d, where the 'x's are the hexadecimal values of the six high-order 16-bit pieces of the address, and the 'd's are the decimal values of the four low-order 8-bit pieces of the address (standard IPv4 representatio..
Select the valid IPv6 addresses: (Choose all apply) A B C D :: ::192:168:0:1 2002:coa8:101::42 2003:dead:beef:4dad:23:46:bb:101
P4s answer: A B C D
Which 3 of the following are ipv6 transition mechanisms? A. B. C. D. 6to4 tunneling GRE tunneling SATAP tunneling Teredo tunneling
Correct: A C D
Which 2 statements describe characterstics of IPV6 unicast addressing? 1 If a global is assigned to an interface, then that is the only allowable address for the interface. 2 global addresses start with 2000::/3 3 Link -local addresses staet with FF00:/12 4 Link local addresses start with FF00:/10 5 There is only one loopback address and it is :: 2.5
Hi Chris > 1) :: > 2) ::192:168:0:1 > 3) 2000:: > 4) 2001:3452:4952:2837:: > 5) 2002:c0a8:101::42 > 6) 2003:dead:beef:4dad:23:46:bb:10 > 1,2,5 & 6 are correct answers, as: 1. is a network address 2. is valid
3. is not a valid ip address, it is only a subnet, actual interface address is missing 4. same as 3 5. is a contraction of IPv6 address 6. is a normal IPv6 address Q) Which 3 of the following are ipv6 transition mechanisms? A. B. C. D. 6to4 tunneling GRE tunneling ISATPA tunneling Teredo tunneling
2. Which two statements describe characteristics of IPv6 unicast addressing? (Choose two.) A. B. C. D. Global addresses start with 2000::/3. Link-local addresses start with FE00:/12. Link-local addresses start with FF00::/10. There is only one loopback address and it is ::1.
Answer: A, D
A. B. C. D. E. F.
::192:168:0:1 2002:c0a8:101::42 2000:: :: 2001:3452:4952:2837:: 2003:dead:beef:4dad:23:46:bb:101
A,B,D,F
Which 3 of the following are ipv6 transition mechanisms? A. 6to4 tunneling B. GRE tunneling C. ISATPA tunneling D. Teredo tunneling Chris 04-01-2009 A,C & D - Beware, you will have to select from 6 options in CCNA Exam