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Energy

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Energy
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posted:
11/25/2011
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Energy

Students will:

a) Identify several forms of

energy.

b) Calculate kinetic energy for

an object

c) Calculate potential energy

for an object

1

Kinetic Energy

• Kinetic Energy is the

energy of an object due

to its motion.









2

Kinetic Energy





KE  mv 1

2

2



m  mass

v  velocity

3

Kinetic Energy

•Sample Problem 5B.1

A 7.00 kg bowling ball

moves at 3.00 m/s.

How much kinetic energy

does the bowling ball

have?

4

Kinetic Energy

• Sample Problem 5B

mb = 7.00 kg KEb = ?

vb = 3.00 m/s

KEb = (½)mv 2



KEb = (½)(7.00 kg)(3.00 m/s)2

KEb = 31.5 J 5

Kinetic Energy

•Sample Problem 5B.2

How fast must a 2.45 g

ping-pong ball move in

order to have the same

kinetic energy as the

bowling ball?

6

Kinetic Energy

•Sample Problem 5B.2

mpp = 2.45x10-3 kg KEb = 31.5 J = KEpp

KEpp = (½)mtvt2 vpp = ?



31.5 J = (½)(2.45x10-3 kg)vpp2

( 2)( 31.5J )

v pp 

( 2.45  10  3 kg )

vpp = 1.60x102 m/s (358 miles per hour)

7

Kinetic Energy



Problems

p 174 #1-5



Work on this

assignment for

30 minutes. 8

P 174 #1-5









9

Kinetic Energy

Problems p 174

1) v = 170 m/s

2) v = 38.8 m/s

3) KEA = 2.4 J KEB = 4.8 J

4) KEA = 2.4 J KEB = 9.6 J

5) m = 1600 kg

10

Potential Energy



• Potential Energy is the

energy of an object due to

the position of the object.







11

Gravitational

Potential Energy

• Gravitational potential

energy is associated with an

object due to the position of

the object relative to the

Earth or some other

gravitational source.

12

Gravitational

Potential Energy



PE g = mgh

m = mass

g = gravity

h = height

13

Elastic

Potential Energy

• Elastic potential energy is

the potential energy in a

stretched or compressed

spring.



14

Elastic

Potential Energy



PEelastic = kx 1

2

2



k = spring constant

x = distance compressed

or stretched

15

Potential Energy

•Sample Problem 5D

A 70.0 kg stuntman is attached to a

bungee cord with an unstretched length of

15.0 m. He jumps off a bridge spanning a

river from a height of 50.0 m. When he

finally stops, the cord has a stretched

length of 44.0 m. Treat the stuntman as a

point mass, and disregard the weight of

the bungee cord. Assuming the spring

constant of the bungee cord is 71.8 N/m,

what is the total potential energy relative

to the water when the man stops falling?16

Potential Energy

•Sample Problem 5D

m = 70.0 kg k = 71.8 N/m

h = 50.0 m – 44.0 m = 6.0 m

x = 44.0 m – 15.0 m = 29.0 m

Peg = ?

PEelastic = ?

PEtotal = ?



17

Potential Energy

PE g  mgh

 

PE g  70.0 kg  9.81 s 2 6.0 m 

m





PE g  4100 J





PE elastic  1 kx 2

2



PE elastic  1

2

71.8 m 29 m 2

N





PE elastic  30200 J





PE total  PE g  PE elastic

PE total  4100 J  30200 J

PE total  34300 J 18

Potential Energy



Problems

p 180 #1-3

Work on this

assignment for

30 minutes.

19

P 180 #1-5









20

Potential Energy

Problems p 180

1) PEelastic = 3.3 J

2) PEelastic = 0.031 J

3) a) PEg = 785 J

b) PEg = 105 J

c) PEg = 0.00 J 21


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