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Nucleic Acid Chemistry

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Nucleic Acid Chemistry
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Nucleic Acid Chemistry



Where the info is…interpreting the

blueprint

Central Dogma



Replication









DNA ---------------- RNA-------------- protein

transcription translation

Central Dogma

• Replication

– DNA making a copy of itself

• Making a replica

• Transcription

– DNA being made into RNA

• Still in nucleotide language

• Translation

– RNA being made into protein

• Change to amino acid language

Replication

• Remember that DNA is self

complementary

• Replication is semiconservative

– One strand goes to next generation

– Other is new

• Each strand is a template for the other

– If one strand is 5’ AGCT 3’

– Other is: 3’ TCGA 5’

Replica

• Write the strand complementary to:







3’ ACTAGCCTAAGTCG 5’



Answer

Replication is Semiconservative

Replication

• Roles of enzymes

– Topoisomerases

– Helicase

– DNA polymerases

– ligase

• DNA binding proteins

– DNA synthesis

• Leading strand

• Lagging strand

Replication

Replication

• Helix opens

– Helicase

• Causes supercoiling upstream

– Topoisomerases (gyrase)

• DNA Binding Proteins

– Prevent reannealing

Replication

Replication

• Leading strand

– 3’ end of template

– As opens up, DNA polymerase binds

– Makes new DNA 5’ - 3’

• Same direction as opening of helix

• Made continuously

Replication

Replication

• Lagging strand

– 5’ end of template

• Can’t be made continuously as direction is wrong

– RNA primer

– New DNA made 5’  3’

• Opposite direction of replication

• Discontinuous

– Okazaki fragments

• Ligase closes gaps

Transcription

• DNA template made into RNA copy

– Uracil instead of Thymine

• One DNA strand is template

– Sense strand

• Other is just for replication

– Antisense (not to be confused with

nonsense!)

• In nucleus

– nucleoli

Transcription

• From following DNA strand, determine

RNA sequence



3’ GCCTAAGCTCA 5’



Answer

Transcription

Transcription

• DNA opens up

– Enzymes?

• RNA polymerase binds

– Which strand?

– Using DNA template, makes RNA

• 5’-3’

• Raw transcript called hnRNA

Transcription

How does RNA polymerase know where to

start?

upstream promotor sequences

Pribnow Box

TATA box

RNA polymerase starts transcription X

nucleotides downstream of TATA box

Introns and Exons

• Introns

– Intervening sequences

– Not all DNA codes for protein

– Regulatory info, “junk DNA”

• Exons

– Code for protein

Processing of hnRNA into mRNA

• 3 steps

– Introns removed

• Self splicing

– 5’ methyl guanosine cap added

– Poly A tail added

• Moved to cytosol for translation

Processing of hnRNA into mRNA

Translation

• RNA -- Protein

– Change from nucleotide language to amino

acid language

• On ribosomes

• Vectorial nature preserved

– 5’ end of mRNA becomes amino terminus of

protein

– Translation depends on genetic code

Genetic Code

• Nucleotides read in triplet “codons”

– 5’ - 3’

• Each codon translates to an amino acid

• 64 possible codons

– 3 positions and 4 possiblities (AGCU) makes

43 or 64 possibilities

– Degeneracy or redundancy of code

• Only 20 amino acids

• Implications for mutations

Genetic Code

Genetic Code

• Not everything translated

• AUG is start codon

– Find the start codon

• Also are stop codons

• To determine aa sequence

– Find start codon

– Read in threes

– Continue to stop codon

Translation

• Steps:

– Find start codon (AUG)

– After start codon, read codons, in threes

– Use genetic code to translate

Translate the following:



GCAGUCAUGGGUAGGGAGGCAACCUGAACCGAC



Answer

Translation Process

• Requires Ribosomes, rRNA, tRNA and, of

course, mRNA

– Ribosome

• Made of protein and rRNA

• 2 subunits

• Has internal sites for 2 transfer RNA molecules

Ribosome









Left is cartoon diagram Right is actual picture

Transfer RNA

• Mostly double stranded

– Folds back on itself

• Several loops

– Anticodon loop

• Has complementary nucleotides to codons

• 3’ end where aa attach

Transfer RNA

Translation

• Initiation

– Ribosomal subunits assemble on mRNA

– rRNA aids in binding of mRNA

• Elongation

– tRNAs with appropriate anticodon loops bind to complex

– have aa attached (done by other enzymes)

– Amino acids transfer form tRNA 2 to tRNA 1

– Process repeats

• Termination

– tRNA with stop codon binds into ribosome

– No aa attached to tRNA

– Complex falls apart

Translation

Translation

• Happening of process (circa 1971)



• http://www.youtube.com/watch?v=u9dhO0

iCLww

Mutations

• Changes in nucleotide sequence

• Can cause changes in aa sequence

– Degeneracy in genetic code can prevent

• Two types

– Point mutations

• Single nucleotide changes

– Frame shift

• Insertions or deletions

Point Mutations

• Single nucleotide changes

• Old sequence

AUG GGU AGG GAG GCA ACC UGA ACC GAC

aa: G R E A T



New sequence

AUG GGU AGU GAG GCA ACC UGA ACC GAC

aa: G S E A T

Point mutations

• Depending on change, may not change aa

sequence

• Old sequence

AUG GGU AGG GAG GCA ACC UGA ACC GAC

aa: G R E A T



New sequence

AUG GGU AGA GAG GCA ACC UGA ACC GAC

aa: G R E A T

Point Mutations

• Change could make little difference

– If valine changed to leucine, both nonpolar

• Change could be huge,

– Could erase start codon

• Old sequence

AUG GGU AGG GAG GCA ACC UGA ACC GAC

aa: G R E A T



New sequence

AUU GGU AGA GAG GCA ACC UGA ACC GAC

aa: no start codon…protein not made

Point Mutations

• Other possibilities,

– Stop codon inserted

• Truncated protein

– Stop codon changed

• Extra long protein

• Bottom line,

– Depends on what change is

Frame Shift mutations

• Insertions or deletions

– Change the reading frame

• Insertion example

Old sequence

AUG GGU AGG GAG GCA ACC UGA ACC GAC

aa: G R E A T



New sequence

AUG GGU AGG AGA GGC AAC CUG AAC CGA C

aa: G R R G N L N R

Frame Shift Mutations

• Deletion example

• Old sequence

AUG GGU AGG GAG GCA ACC UGA ACC GAC

aa: G R E A T



New sequence Delete second A (Underlined above)



AUG GGU GGG AGG CAA CCU GAA CCG AC

aa: G G R Q P G P

Complementary DNA Strand

Template:





3’ ACTAGCCTAAGTCG 5’

5’ TGATCGGATTCAGC 3’



Back

RNA Transcript





DNA 3’ GCCTAAGCTCA 5’

RNA 5’ CGGAUUCGAGU 3’



Back

Translation Answer

Find start codon



GCAGUCAUGGGUAGGGAGGCAACCUGAACCGAC



Read in threes after that:



AUG GGU AGG GAG GCA ACC UGA ACC GAC



Using Genetic code



AUG GGU AGG GAG GCA ACC UGA ACC GAC



G R E A T stop



After stop codon…rest is garbage



Back


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