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Chapter 7

Pretest



1. Which of the following is an example of a physical change?

a. Wood burns and becomes ash.

b. A steel nail rusts over time.

c. Ice melts and becomes water.

d. Milk curdles when acid is added to it.





2. Which of the following characteristics can you determine about a

substance based on its chemical formula?

a. the number and types of atoms that make up the substance

b. the mass of an unknown sample of the substance

c. the melting point of the substance

d. the density and state of the substance at room temperature







Go to section

Chapter 7

Pretest (continued)



3. How do you find the atomic mass of an element?





4. Which conversion factor would you multiply 0.020 m by in

order to express the quantity in centimeters?

a. 1000 m/1 km

b. 1 km/1000 m

c. 1 m/100 cm

d. 100 cm/1 m





5. Which is the correct chemical formula for potassium

hydroxide?

a. POH b. KOH

c. P5OH d. K2OH



Go to section

• A chemical reaction is the process by which one or

more substances are changed into one or more

different substances.



• In any chemical reaction, the original substances are

known as the reactants and the resulting substances

are known as the products.



• According to the law of conservation of mass, the

total mass of reactants must equal the total mass of

products for any given chemical reaction.



Go to section

Section 7.1

Interest Grabber



Equation Analogy

Imagine that you work at a skateboard shop and you are in

charge of assembling the skateboards. Every skateboard

requires one deck (the board), two trucks (the mounted axles),

and four wheels.

1. Your boss asks you to make five skateboards. How many

trucks do you need?

2. The following diagram shows the “recipe” for one

skateboard. What do you notice about the relative

amounts of each part on either side of the arrow?









Go to section

• A chemical equation represents, with symbols and

formulas, the identities and relative molecular or

molar amounts of the reactants and products in a

chemical reaction.



• example: The following chemical equation shows

that the reactant ammonium dichromate yields

the products nitrogen, chromium(III) oxide, and

water.



(NH4)2Cr2O7(s) N2(g) + Cr2O3(s) + 4H2O(g)

Go to section

Indications of a Chemical Reaction

• Certain easily observed changes usually indicate

that a chemical reaction has occurred.

1. Evolution of energy as heat and light

2. Production of a gas

3. Formation of a precipitate.

• A solid that is produced as a result of a

chemical reaction in solution and that

separates from the solution is known as a

precipitate.

4. Color change

Go to section

Characteristics of Chemical Equations

• The following requirements will aid you in writing and

reading chemical equations correctly.

1. The equation must represent known facts.

2. The equation must contain the correct formulas

for the reactants and products.

3. The law of conservation of mass must be satisfied.

• A coefficient is a small whole number that

appears in front of a formula in a chemical

equation.



Go to section

Elements That Normally Exist as

Diatomic Molecules









Go to section

Characteristics of Chemical Equations,

continued

Word and Formula Equations

• The first step in writing a chemical equation is to

identify the facts to be represented.



• A word equation is an equation in which the reactants

and products in a chemical reaction are represented by

words.

• A word equation is qualitative

• example: methane + oxygen carbon dioxide + water





Go to section

Characteristics of Chemical Equations,

continued

Word and Formula Equations, continued

• The next step in writing a correct chemical equation is

to replace the names of the reactants and products with

appropriate symbols and formulas.



• A formula equation represents the reactants and

products of a chemical reaction by their symbols or

formulas.

• example: The formula equation for the reaction of methane

and oxygen is

CH4(g) + O2(g) CO2(g) + H2O(g) (not balanced)

Go to section

Characteristics of Chemical Equations,

continued

Word and Formula Equations, continued

• To complete the process of writing a correct equation,

the law of conservation of mass must be taken into

account.

• The relative amounts of reactants and products

represented in the equation must be adjusted so

that the numbers and types of atoms are the same

on both sides of the equation.

• This process is called balancing an equation

and is carried out by inserting coefficients.

Go to section

Characteristics of Chemical Equations,

continued

Word and Formula Equations, continued

• To balance the equation, begin by counting atoms of

elements that are combined with atoms of other

elements and that appear only once on each side of the

equation.

CH4(g) + O2(g) CO2(g) + 2H2O(g) (not balanced)

• Begin by counting carbon atoms.

• Carbon is already balanced in the equation.

• Two additional hydrogen atoms are needed on the right

side of the equation.

Go to section

Characteristics of Chemical Equations,

continued

Word and Formula Equations, continued

CH4(g) + O2(g) CO2(g) + 2H2O(g) (partially balanced)

• Now consider the number of oxygen atoms.

• Increase the number of oxygen atoms on the left side to four

by placing the coefficient 2 in front of the molecular formula

for oxygen.

• The correct chemical equation, or balanced formula

equation, for the burning of methane in oxygen is

CH4(g) + 2O2(g) CO2(g) + 2H2O(g)

Go to section

Characteristics of Chemical Equations, continued

Additional Symbols Used in Chemical Equations









Go to section

Characteristics of Chemical Equations, continued

Additional Symbols Used in Chemical Equations









Go to section

Symbols Used in Chemical Equations









Go to section

Methane Combustion









Go to section

• A chemical formula indicates:

– the elements present in a compound

– the relative number of atoms or ions of each element

present in a compound

• Chemical formulas also allow chemists to calculate a

number of other characteristic values for a compound:

– formula mass

– molar mass

– percentage composition





Go to section

Characteristics of Chemical Equations,

continued

Sample Problem A

Write word and formula equations for the chemical

reaction that occurs when solid sodium oxide is added to

water at room temperature and forms sodium hydroxide

(dissolved in the water). Include symbols for physical

states in the formula equation. Then balance the formula

equation to give a balanced chemical equation.









Go to section

Characteristics of Chemical Equations,

continued

Sample Problem A Solution

• The word equation must show the reactants, sodium oxide and

water, to the left of the arrow.

• The product, sodium hydroxide, must appear to the right of the

arrow.



sodium oxide + water sodium hydroxide

• Sodium has an oxidation state of +1, that oxygen usually has an

oxidation state of 2, and that a hydroxide ion has a charge of 1.

The unbalanced formula equation is

Na2O + H2O NaOH (not balanced)

Go to section

Characteristics of Chemical Equations,

continued

Sample Problem A Solution, continued

Adding symbols for the physical states of the reactants and products

and the coefficient 2 in front of NaOH produces a balanced chemical

equation.



Na2O(s) + H2O(l) 2NaOH(aq)









Go to section

Significance of a Chemical Equation



• Some of the quantitative information revealed by a

chemical equation includes

1. The coefficients of a chemical reaction indicate

relative, not absolute, amounts of reactants and

products.



H2(g) + Cl2(g) 2HCl(g)

1 molecule H2 : 1 molecule Cl2 : 2 molecules HCl

• This ratio shows the smallest possible relative

amounts of the reaction’s reactants and products.

Go to section

Significance of a Chemical Equation



2. The relative masses of the reactants and products

of a chemical reaction can be determined from the

reaction’s coefficients.

• An amount of an element or compound in moles can be

converted to a mass in grams by multiplying by the

appropriate molar mass.

• example:

2.02 g H2

1 mol H2   2.02 g H2

mol H2





Go to section

Interpreting a Chemical Reaction









Go to section

Significance of a Chemical Equation

3. The reverse reaction for a chemical equation has

the same relative amounts of substances as the

forward reaction.

• An equation gives no indication of whether a reaction

will actually occur.



• Chemical equations give no information about the

speed at which reactions occur.

• Equations do not give any information about how

the bonding between atoms or ions changes

during the reaction.

Go to section

Balancing Chemical Equations



• The following procedure demonstrates how to master

balancing equations by inspection using a step-by-

step approach.





1. Identify the names of the reactants and the

products, and write a word equation.



water hydrogen + oxygen





Go to section

Balancing Chemical Equations, continued

• balancing equations by inspection, continued



2. Write a formula equation by substituting correct

formulas for the names of the reactants and the

products.



H2O(l) H2(g) + O2(g) (not balanced)









Go to section

Balancing Chemical Equations, continued

• balancing equations by inspection, continued

3. Balance the formula equation according to the law

of conservation of mass.

• Balance the different types of atoms one at a time.

• First balance the atoms of elements that are combined

and that appear only once on each side of the equation.

• Balance polyatomic ions that appear on both sides of

the equation as single units.

• Balance H atoms and O atoms after atoms of all other

elements have been balanced.



Go to section

Balancing Chemical Equations, continued

• balancing equations by inspection, continued

4. Count atoms to be sure that the equation is

balanced.

2H2O(l) 2H2(g) + O2(g)

(4H + 2O) = (4H) + (2O)



• If the coefficients do not represent the smallest possible

whole-number ratio of reactants and products, divide the

coefficients by their greatest common factor in order to

obtain the smallest possible whole-number coefficients.

Go to section

Balancing Chemical Equations, continued



Sample Problem C

The reaction of zinc with aqueous hydrochloric acid

produces a solution of zinc chloride and hydrogen gas.

Write a balanced chemical equation for the reaction.









Go to section

Balancing Chemical Equations, continued



Sample Problem C Solution





• Write the word equation.

zinc + hydrochloric acid zinc chloride + hydrogen



• Write the formula equation.

Zn(s) + HCl(aq) ZnCl2(aq) + H2(g) (not balanced)





Go to section

Section 7.1

Reading Strategy



Monitoring Your Understanding









a. and c. How to balance chemical equations and how to convert

from mass to moles.









Go to section

Formula Masses

• The formula mass of any molecule, formula unit, or ion is

the sum of the average atomic masses of all atoms

represented in its formula.

– example: formula mass of water, H2O

average atomic mass of H: 1.01 amu

average atomic mass of O: 16.00 amu

1.01 amu

2 H atoms   2.02 amu

H atom

16.00 amu

1 O atom   16.00 amu

O atom

average mass of H2O molecule: 18.02 amu

Go to section

Formula Masses

• The mass of a water molecule can be referred to as a

molecular mass.

• The mass of one formula unit of an ionic compound, such

as NaCl, is not a molecular mass.

• The mass of any unit represented by a chemical formula

(H2O, NaCl) can be referred to as the formula mass.









Go to section

Formula Masses, continued

Sample Problem F

Find the formula mass of potassium chlorate, KClO3.









Go to section

Formula Masses, continued

Sample Problem F Solution

The mass of a formula unit of KClO3 is found by adding

the masses of one K atom, one Cl atom, and three O

atoms.

Atomic masses can be found in the periodic table in the

back of your book.

In your calculations, round each atomic mass to two

decimal places.







Go to section

Formula Masses, continued

Sample Problem F Solution, continued



39.10 amu

1 K atom   39.10 amu

K atom

35.45 amu

1 Cl atom   35.45 amu

Cl atom

16.00 amu

3 O atoms   48.00 amu

O atom

formula mass of KClO3 = 122.55 amu

Go to section

Figure 2

Burning of Carbon









Go to section

Figure 2

Burning of Carbon









Go to section

Figure 2

Burning of Carbon









Go to section

Go to section

Balancing Chemical Section 7.1



Equations









Go to section

Balancing Chemical Section 7.1



Equations









Go to section

Balancing Chemical Section 7.1



Equations









Go to section

Balancing Chemical Section 7.1



Equations









Go to section

Calculations With Figure 8

Chemical Equations









Go to section

Calculations With Figure 8

Chemical Equations









Go to section

Calculations With Figure 8

Chemical Equations









Go to section

Calculations With Figure 8

Chemical Equations









Go to section

Calculations With Figure 8

Chemical Equations









Go to section

Molar Masses

• The molar mass of a substance is equal to the mass in

grams of one mole, or approximately 6.022  1023

particles, of the substance.

– example: the molar mass of pure calcium, Ca, is 40.08 g/mol

because one mole of calcium atoms has a mass of 40.08 g.



• The molar mass of a compound is calculated by adding the

masses of the elements present in a mole of the molecules

or formula units that make up the compound.









Go to section

Molar Masses, continued

• One mole of water molecules contains exactly two moles

of H atoms and one mole of O atoms. The molar mass of

water is calculated as follows.



1.01 g H

2 mol H   2.02 g H

mol H

16.00 g O

1 mol O   16.00 g O

mol O

molar mass of H2O molecule: 18.02 g/mol

• A compound’s molar mass is numerically equal to its

formula mass.

Go to section

Calculating Molar Masses for Ionic Compounds









Go to section

Molar Masses, continued

Sample Problem G

What is the molar mass of barium nitrate, Ba(NO3)2?









Go to section

Molar Masses, continued

Sample Problem G Solution

One mole of barium nitrate, contains one mole of Ba, two moles of

N (1  2), and six moles of O (3  2).

137.33 g H

1 mol Ba   137.33 g Ba

mol Ba

14.01 g

2 mol N   28.02 g N

mol N

16.00 g O

6 mol O   96.00 g O

mol O

molar mass of Ba(NO3)2 = 261.35 g/mol

Go to section

Molar Mass as a Conversion Factor

• The molar mass of a compound can be used as a

conversion factor to relate an amount in moles to a mass

in grams for a given substance.

• To convert moles to grams, multiply the amount in moles

by the molar mass:





Amount in moles  molar mass (g/mol)

= mass in grams







Go to section

Mole-Mass Calculations









Go to section

Molar Mass as a Conversion Factor, continued

Sample Problem H

What is the mass in grams of 2.50 mol of oxygen gas?









Go to section

Molar Mass as a Conversion Factor, continued



Sample Problem H Solution

Given: 2.50 mol O2

Unknown: mass of O2 in grams

Solution:

moles O2 grams O2



amount of O2 (mol)  molar mass of O2 (g/mol) = mass of

O2 (g)





Go to section

Molar Mass as a Conversion Factor, continued

Sample Problem H Solution, continued

Calculate the molar mass of O2.



16.00 g O

2 mol O   32.00 g

mol O



Use the molar mass of O2 to convert moles to mass.

32.00 g O2

2.50 mol O2   80.0 g O2 80.0 g O2

mol O2



Go to section

Converting Between Amount in Moles and

Number of Particles









Go to section

Molar Mass as a Conversion Factor, continued

Sample Problem I

Ibuprofen, C13H18O2, is the active ingredient in many

nonprescription pain relievers. Its molar mass is

206.31 g/mol.

a. If the tablets in a bottle contain a total of 33 g of

ibuprofen, how many moles of ibuprofen are in the

bottle?

b. How many molecules of ibuprofen are in the bottle?

c. What is the total mass in grams of carbon in 33 g

of ibuprofen?



Go to section

Molar Mass as a Conversion Factor, continued

Sample Problem I Solution

Given: 33 g of C13H18O2

molar mass 206.31 g/mol



Unknown: a. moles C13H18O2

b. molecules C13H18O2

c. total mass of C

Solution: a. grams moles

1 mol C13H18O2

g C13H18O2   mol C13H18O2

206.31 g C13H18O2

Go to section

Molar Mass as a Conversion Factor, continued

Sample Problem I Solution, continued



b. moles molecules



6.022  1023 molecules

mol C13H18O2   molecules C13H18O2

mol



c. moles C13H18O2 moles C grams C



13 mol C 12.01 g C

mol C13H18O2    gC

mol C13H18O2 mol C



Go to section

Molar Mass as a Conversion Factor, continued

Sample Problem I Solution, continued 0.16 mol



1 mol C13H18O2

33 a. C13H18O2 

g  0.16 mol C13H18O2

206.31 g C13H18O2



b. 0.16mol C H O  6.022  1023 molecules

13 18 2



mol

9.6  1022 molecules C13H18O2



13 mol C 12.01 g C

c. 0.16 mol C H O    25 g C

13 18 2

mol C13H18O2 mol C



Go to section

Section 7.2









Models of Reactions

The following drawings 1. Synthesis means “putting

represent reactants and something together.”

products of three different

chemical reactions.



Reaction B is a synthesis

reaction, because the

two reactants come

together to make one

product.







Go to section Click the mouse button to display the answer.

Section 7.2









Models of Reactions

The following drawings 2. Decomposition means

represent reactants and “taking something apart.”

products of three different

chemical reactions.



Reaction A is a

decomposition reaction,

because the reactant is

taken apart to make two

products.







Go to section Click the mouse button to display the answer.

Section 7.2









Models of Reactions

The following drawings 3. Replacement means

represent reactants and “something taking the

products of three different place of another.”

chemical reactions.





Reaction C is a

replacement reaction,

because one reactant

takes the place of part

of another.





Go to section Click the mouse button to display the answer.

Section 7.2

Reading Strategy



Previewing









a. Decomposition

b. Double Replacement

c. AB → A + B

d. A + BC → B + AC

e. AB + CD → AD + CB

Go to section

Section 7.3

Interest Grabber



Exothermic and Endothermic Processes

Energy is either absorbed or released during chemical and

physical changes. During an endothermic change, energy is

absorbed from the surroundings. During an exothermic

change, energy is released to the surroundings. Two

different physical changes are described below. Read each

description and decide if the change is exothermic or

endothermic.

1. A plastic bottle of water is placed in a freezer. After

several hours, the water has frozen solid.

2. A chef places a stick of solid butter in a saucepan, and

heats the saucepan over low heat on a stove. After

several minutes, the stick of butter has melted.

Go to section

Section 7.3

Reading Strategy



Comparing and Contrasting









a. releases energy to the surroundings

b. absorbs energy from surroundings



Go to section

Figure 17

Combustion of Propane









Go to section

Figure 17

Combustion of Propane









Go to section

Figure 17

Combustion of Propane









Go to section

Figure 17

Combustion of Propane









Go to section

Reaction Energy Diagram for Figure 18A

an Exothermic Reaction









Go to section

Reaction Energy Diagram for Figure 18A

an Exothermic Reaction









Go to section

Reaction Energy Diagram for Figure 18B

an Endothermic Reaction









Go to section

Reaction Energy Diagram for Figure 18B

an Endothermic Reaction









Go to section

Section 7.4

Interest Grabber



Changing Reaction Rate

1. Place one effervescent antacid tablet into a plastic cup

filled with hot tap water and a second tablet into a plastic

cup filled with cold water at the same time. In which cup

did the fizzing last longer?

2. On a small piece of paper, crush a third tablet into a

powder using a plastic spoon. Place the crushed tablet

into a cup of cold water and a fourth (whole) tablet into

another cup of cold water at the same time. In which cup

did the fizzing last longer?

3. How does temperature affect the rate of fizzing?

4. How does crushing the reactant into a powder affect the

rate of fizzing?

Go to section

Section 7.4

Reading Strategy



Building Vocabulary









a. Temperature d. Concentration

b. Surface area e. Catalysts

c. Stirring

Go to section

Reaction Energy Diagram for a Figure 23

Catalyzed and an Uncatalyzed

Reaction









Go to section

Section 7.5

Interest Grabber



Opposing Changes

Imagine that you are emptying a swimming pool using a

pump that removes 5 gallons of water each minute.

Meanwhile, your friend turns on a hose that adds 5 gallons of

water to the pool each minute.

1. What happens to the water level of the

swimming pool?

2. What would happen to the water level of the swimming

pool if you increased the rate that the pump removed

water to 7 gallons of water each minute?









Go to section

Section 7.5

Reading Strategy



Outlining









1. Physical equilibrium B. Factors affecting chemical equilibrium

2. Chemical equilibrium 3. Concentration

Go to section

Figure 25

Physical Equilibrium









Go to section

Chapter 7

Pretest Answers



1. Which of the following is an example of a physical change?

a. Wood burns and becomes ash.

b. A steel nail rusts over time.

c. Ice melts and becomes water.

d. Milk curdles when acid is added to it.





2. Which of the following characteristics can you determine about a

substance based on its chemical formula?

a. the number and types of atoms that make up the substance

b. the mass of an unknown sample of the substance

c. the melting point of the substance

d. the density and state of the substance at room temperature







Click the mouse button to display the answers.

Chapter 7

Pretest Answers

(continued)





3. How do you find the atomic mass of an element?

The atomic mass of each element is listed on the periodic table.

4. Which conversion factor would you multiply 0.020 m by in

order to express the quantity in centimeters?

a. 1000 m/1 km

b. 1 km/1000 m

c. 1 m/100 cm

d. 100 cm/1 m





5. Which is the correct chemical formula for potassium

hydroxide?

a. POH b. KOH

c. P5OH d. K2OH



Click the mouse button to display the answers.

Section 7.1

Interest Grabber

Answers



1. Your boss asks you to make five skateboards. How many

trucks do you need?

10

2. The following diagram shows the “recipe” for one skateboard.

What do you notice about the relative amounts of each part

on either side of the arrow?

There are the same numbers of each part on either side of

the arrow.

Section 7.3

Interest Grabber

Answers



1. A plastic bottle of water is placed in a freezer. After

several hours, the water has frozen solid.

Exothermic. The liquid water releases energy as it

changes into ice.

2. A chef places a stick of solid butter in a saucepan, and

heats the saucepan over low heat on a stove. After

several minutes, the stick of butter has melted.

Endothermic. The solid butter absorbs energy as it

changes into liquid.

Section 7.4

Interest Grabber

Answers



1. Place one effervescent antacid tablet into a plastic cup filled with hot

tap water and a second tablet into a plastic cup filled with cold water

at the same time. In which cup did the fizzing last longer?

The fizzing lasts longer for the tablet placed in cold water.

2. On a small piece of paper, crush a third tablet into a powder using a

plastic spoon. Place the crushed tablet into a cup of cold water and

a fourth (whole) tablet into another cup of cold water at the same

time. In which cup did the fizzing last longer?

The fizzing lasts longer for the whole, uncrushed tablet.

3. How does temperature affect the rate of fizzing?

Increased temperature caused the fizzing to happen at a faster rate.

4. How does crushing the reactant into a powder affect the rate of

fizzing?

Crushing the reactant into a powder caused the fizzing to happen at

a faster rate.

Section 7.5

Interest Grabber

Answers



1. What happens to the water level of the swimming pool?

The water level stays the same.

2. What would happen to the water level of the swimming

pool if you increased the rate that the pump removed

water to 7 gallons of water each minute?

The water level would go down.

Chapter 7

Go Online



Self-grading assessment



Articles on chemical reactions



For links on conservation of mass, go to www.SciLinks.org

and enter the Web Code as follows: ccn-1071.

For links on oxidation and reduction, go to www.SciLinks.org

and enter the Web Code as follows: ccn-1072.

For links on factors affecting reaction rate, go to

www.SciLinks.org and enter the Web Code as

follows: ccn-1074.

For links on factors affecting equilibrium, go to

www.SciLinks.org and enter the Web Code as

follows: ccn-1075.

For links on chemical reactions, go to www.SciLinks.org

and enter the Web Code as follows: ccn-1076.



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