BONUS ASSIGNMENT Read the following mini-lesson and follow the examples provided. Do not turn anything in to me. On the Final Exam, two optional questions will be provided on this topic. If you get these questions correct, I will replace your lowest homework or quiz score with a perfect score. Motivation (Section 8.1) All semester we have assumed that we know or can calculate the mean and variance of a population. However, we usually do not know the true population mean or standard deviation for a random variable. For example, we might say that X = the weight of a milk container, and assume that X has a normal distribution with mean 2.012 liters and variance 0.23… but do we really know the average weight of ALL milk containers? Obviously not. These numbers are really just our best guess. This “best guess” comes from collecting data. We would collect milk cartons, calculate the mean and variance of the entire sample, and use these numbers as our estimates. In statistics, we use confidence intervals to determine how accurate these estimates are. In MTH 352, we discuss confidence intervals in great detail. However, for now, we only need to know how they are calculated. Calculation: To estimate the parameters for the milk carton example, suppose we collect 50 milk cartons and weigh them. The dataset of milk weights is given on page 269 of your textbook. It turns out that the average (x ) and standard deviation ( s ) of this data set are as follows: x = 2.0727 liters s = 0.0711 liters In section 8.1, we learn how to use the t-distribution to build a confidence interval aroundx. This will give us an idea of our accuracy level. The required equation is in the blue box on page 328. This calculation involves five numbers: x, s, n (the sample size), a t-statistic, and . Think of as being the “leftover probability”. So for a 90% confidence interval, = 10% (i.e. 0.10); for a 95% confidence interval, = 5% (i.e., 0.05); etc. Lastly, keep in mind that to calculate the t-statistic, you will have to split in half. For example if you have n = 50 data points, then a 95% confidence interval will have = 0.05 and the t-statistic that you will be looking up in the table is t t 0.05 t 0.025, 49 .This , n 1 , 501 2 2 value is not in the table since there is not a row for 49 degrees of freedom… but using a computer would tell us that this is about 2.0096). Finally, read example 17 on page 329, example 45 on page 334, and complete 8.1.1 on page 340. The computation question on the exam will be similar to these sample problems.
Pages to are hidden for
"confidence intervals"Please download to view full document