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Introduction to Statistics: Test 2 Review Handout

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Introduction to Statistics: Test 2 Review Handout
Probability

• Probability is the likelihood of a particular outcome occurring.



Law of Large Numbers

• As we repeat an experiment a large number of times, the ratio of the number of successes in the sample to the total number of trials will approach the probability of the event. • Example: proportion of heads should go to .5

10 coins: 100 coins: 1000 coins: 10000 coins: 7H 53 H 498 H 5002 H 3T 47 T 502 T 4998 T p = .7 p = .53 p = .498 p = .5002



• Example: probability of drawing a club from a deck of cards



• Example: in an urn full of 10 red marbles and 12 black marbles, the probability of drawing a black marble is

p= 12 12 = 10 + 12 22



Types of Probabilities

• Classical/Relative Frequency



Probability Definitions

• Sample Space

– S = list of all possible events that can occur – Example: faces of a die, S = {1,2,3,4,5,6}



• Subjective

– Likelihood of an event is based on your own personal judgment



• Event

– Subset of the sample space, one particular outcome of interest – Example: rolling an even number: E = {2,4,6} – Probability of rolling an even is 3 / 6 = .5



Example of a Venn Diagram



Probability Definitions

• A and B (intersection)

– A and B both occur together



• A or B (union)

– Either A occurs or B occurs or both occur



Probability (HW 5.3)

• Sample Space = {1,2,3,4,5,6,7,8} F = {6,7,8} G = {1,3,5,7}

• List outcomes in (F and G), compute P(F and G)



Probability Definitions

• A complement

– All possible events that are not in A



• Example:

– A = it’s snowing – Ac = it’s not snowing



• List outcomes in (F or G), compute P(F or G)



Probability (HW 5.3)

• Sample Space = {1,2,3,4,5,6,7,8} E = {2,3,4,5} • List the outcomes in E-complement.



Disjoint Sets

• Two events are disjoint if they contain no common elements • Disjoint sets cannot happen at the same time • Example: drawing a card that is both a club and a diamond; impossible



• Compute P(E-complement).



Disjoint Sets (HW 5.3)

• Sample Space = {1,2,3,4,5,6,7,8} E = {2,3,4,5} F = {6,7,8} G = {1,3,5,7} • Pick out the two disjoint sets.



Disjoint Sets (HW 5.3)

E = {2,3,4,5} F = {6,7,8} • Compute P(E and F) • Compute P(E or F)



Addition Rule and Complement

• General formula: P(A or B) = P(A) + P(B) – P(A and B)



Addition Rule Example

• We pick a card from a deck of 52 cards.

D = diamond drawn A = ace drawn P(D) = P(A) P(A and D) =



• If A and B are disjoint sets, then P(A or B) = P(A) + P(B) (special case)



• What is P(A or D) ? • What is P(Ac) ?



• Complement probability: P(Ac) = 1 – P(A)



Independence

• Two events A and B are independent if the following formula is true: P(A and B) = P(A) x P(B) • Whether A occurs has nothing to do with whether or not B occurs • A = your salary is more than $50,000 • B = you were born in July



Warning!

• Independent sets and disjoint sets are not the same! • Independent sets:

– P(A and B) = P(A) x P(B) – A and B can occur together, but neither affects the other



• Disjoint sets:

– P(A and B) = 0 – A and B cannot occur together



Independence (HW 5.1-5.2)

• 82% of people who visit an ice cream store buy ice cream. Here is a tree diagram for the sample space of 3 (independent) customers. • Y = Yes (purchase) • N = No (no purchase)



Independence (HW 5.1-5.2)

• 82% of customers buy ice cream. • Find the probability that all three people buy ice cream.



• Find the probability that nobody buys ice cream.



• Find the probability at least one person buys ice cream.



Disjoint vs Independent (HW 5.3)

Let P(A) = .35 and P(B) = .50. Compute P(A or B) if… (i) P(A and B) = .10



Conditional Probability

• The probability that one event occurs, given that another event has already occurred.



(ii) A and B are disjoint



• P (A | B) is read as “probability of A given B.” • If A and B are independent, then the conditional probability of A given B is just the probability of A. • Whether A occurs had nothing to do with whether B occurs, so “given B” should have no effect on A’s probability.



(iii) A and B are independent.



Conditional Probability (HW 5.3)

We have an urn full of marbles of the following colors: 5 green, 4 blue, 3 yellow, 2 red, 1 white (15 total). What’s the probability of drawing a primary color? (Red, yellow, or blue) Given that we drew a primary color, what’s the probability it was either red or yellow?



Checking for Independence

• If any of these formulas hold, A and B are independent:

1. P(A | B) = P(A) 2. P(B | A) = P(B) 3. P(A and B) = P(A) x P(B)



Assuming the marble drawn was not a primary color, what’s the probability it was not green?







If any of these do not hold, A and B are dependent.



Independence (HW 5.3)



Independence (HW 5.3)

• Find the probability the individual stayed in a cabin (C), given that they were at the beach (B).



• Find the probability an individual stayed in a cabin. • Are the events of staying in a cabin (C) and being at the beach (B) independent?



Random Variables

• Discrete

– A countable, whole-number of possible values. – The number of words in a magazine article – The number of clubs in a drawing of 10 cards



Discrete Probability Distribution

Two requirements:

1. Each individual p(x) is between 0 and 1, inclusive 2. All probabilities sum to 1 The mean of a discrete distribution:

MEAN = " x ! p ( x )



• Continuous

– An uncountable, infinite number of possible values, with decimals allowed. – The weight of an athlete – The time taken to complete a race



Also called average, or expected value



Mean of a Distribution (HW 6.1-6.2)

• Here’s a table for the probability of different category hurricanes.



Discrete Mean (HW 6.1-6.3)

• The Cash 4 lottery involves picking 4 numbers, each 0 to 9, and hence 10,000 combinations. If you pick the correct combination, you win $1200. • On a single bet, what’s the probability you win $1200?



Category 1 2 3 4 5



Probability 0.15 0.32 0.12 0.05



• Make a probability distribution for this problem. X is how much you win; find the probabilities with each outcome.



• Find the missing value and the mean/expected value of this data set.



• Is this discrete or continuous?



Discrete Mean (HW 6.1-6.3)

• Find the mean (expected winnings) on this lottery (in dollars). How many cents does this correspond to?



Binomial Distribution

• Requirements:

1. n independent trials (discrete) 2. Each trial takes one of 2 possible outcomes 3. Probability of “success” on each trial is p







Variables in study:

1. n = number of trials 2. p = probability of an individual success



Binomial or Not? (HW 6.1-6.3)

• A student is guessing on a multiple choice quiz, with 10 questions, each with 4 possible choices. X is the number of questions the student gets correct. • A 6-sided die is tossed. X is the number of dots on the top face.



More Binomial Characteristics



More Binomial Characteristics

SUMMARY

• If p .5

Skewed Left Binomial formulas:



mean = n ! p



standard deviation = n ! p ! (1 " p )



StatCrunch Commands

• Binomial Calculator

– Stat > Calculators > Binomial – n, p, x = ?, calculate



Normal Curve (Empirical Rule)

What’s the mean and s.d.?



• Normal Calculator

– Stat > Calculators > Normal – Mean, Standard Deviation – X >= or = 36.9% => 37%





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