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Unit 6 Review

Kinetics and Thermochemistry

Wednesday 5/4

Have phase diagram hw out right away

please









AFTER SCHOOL REVIEW WILL BE AWESOME! IT IS ALSO

ON THE WEB FOR THOSE OF YOU WHO CAN’T MAKE IT.

PLEASE COME! 2:20 – 3:15. 5 EXTRA CREDIT POINTS. AND

EXTENSION ON LAST NIGHTS HW.

Unit 6 Review

Kinetics and Thermochemistry



Please take out paper to complete today’s review. Your

notes may also be helpful.



Each part of today’s in class review is worth points.

Please number each slide and complete each section.



You will have a limited amount of time for each section.

Please keep up.

1 - Specific Heat

 What mass of magnesium is present if 250 J

raises the temperature from 25 °C to 27 °C?

Specific heat 1.02 J/gK



 What is the heat capacity of an unknown

metal if 65.5 grams absorbs 1550 J and

undergoes a temperature change of 62.0 C°?

1 - Specific Heat Answers

 What mass of magnesium is present if 250 J

raises the temperature from 25 °C to 27 °C?

Specific heat 1.02 J/g °C

◦ m= 250 J/(1.02 J/g °C x 2 °C) = 122.5 g = 120 g





 What is the heat capacity of an unknown metal if

65.5 grams absorbs 1550 J and undergoes a

temperature change of 62.0 C°?

◦ Cp = 1550J / (65.5 g x 62.0 °C) = 0.382 J/g °C

2 - Calculation of Energy

 How many joules are required to melt 650

grams of water?







 How many joules are required to boil 650

grams of water? Substance Specific Heat (J/g◦C)

H2O (l) 4.184

H2O (steam) 2.02

Water

Heat of fusion = 334 J/g

Heat of vaporization = 2260 J/g

Substance

H2O (l)

Specific Heat (J/g◦C)

4.184

2 - Calculation of

H2O (steam) 2.02 Energy Answers

Water

Heat of fusion = 334 J/g

Heat of vaporization = 2260 J/g





 How many joules are required to melt 650 grams of

water?

◦ Hfusion = 334 J/g x 650 g = 217,100 J = 220,000 J





 How many joules are required to boil 650 grams of

water?

◦ H vap = 2260 J/g x 650 g = 1,469,000 J = 1,500,000J

1. Going from a solid to a gas is an

3- Heat Curve… (exothermic, endothermic) process

because energy is (absorbed, released).

4. Why does sweating help cool you off?









2. During phase changes the temperature

(increases, decreases, remains constant).









3. List the states of matter in order of

increasing kinetic energy.

3- Heat Curve Answers

1. Going from a solid to a gas is an

4. Why does sweating help cool you off? (exothermic, endothermic) process

Sweating happens when water molecules because energy is (absorbed, released).

evaporate (vaporize) from liquid droplets

on your arm to gas. When these high

energy molecules escape they lower the

overall kinetic energy of the remaining

molecules – lowering your body

temperature as a result!









2. During phase changes the temperature

(increases, decreases, remains constant).







3. List the states of matter in order of

increasing kinetic energy.

Solid to liquid to gas

4- Phase Change Diagrams

 Which line represents

the freezing point?

 Which line represents

the boiling point?

 Describe what happens

a the triple point?

 Describe what happens

at the critical point?

4 - Phase Change Diagrams Answers

 Which line represents the freezing

point? (fusion line)



 Which line represents the boiling

point? (vaporization line)



 Describe what happens a the triple

point? (all 3 states exist

simultaneously)



 Describe what happens at the

critical point? (the liquid state

can no longer exist at these

extremely high temps – no

matter the pressure)

5 - Phase Change Diagram

1. How could you directly

change “Q” to a solid? Q





2. Identify two ways you

could change “Q” to a

gas. Be specific.



3. Describe CLEARLY

what is happening when

A becomes A’.



4. Describe CLEARLY

what is happening when

B becomes B’.

5 - Phase Change Diagram Answers

1. How could you directly change “Q” to a

solid? Q

2. Decrease temp at same pressure.

3. Identify two ways you could change “Q” to

a gas. Be specific.

4. Raise temp at same pressure. OR, lower

pressure at same temp.

5. Describe CLEARLY what is happening

when A becomes A’.

6. Pressure held constant. Solid A heated,

solid A melts at MO, liquid A is heated,

liquid A vaporizes at PO, gaseous A is

heated to A’.

7. Describe CLEARLY what is happening

when B becomes B’.

8. Pressure held constant. Solid B is heated,

solid B sublimates at SO, gaseous B is

heated to B’

6 - Potential Energy Diagrams

 Draw an energy diagram:

Heat of reactants: 4.5 KJ

Heat of products: 10.5 KJ

Energy of activated complex: 15 KJ

Heat of reaction: _____ KJ

Activation Energy: ______ KJ

Exothermic/Endothermic?

How does a catalyst affect this graph?

6 - Potential Energy Diagrams Answers

 Draw an energy diagram:

Heat of reactants: 4.5 KJ

Heat of products: 10.5 KJ

Energy of activated complex: 15 KJ

Heat of reaction: _____ KJ (10.5 – 4.5 = 6 KJ)

Activation Energy: ______ KJ (15 – 4.5 = 10.5 KJ)

Exothermic/Endothermic? ENDOTHERMIC (Products higher

than reactants)

How does a catalyst affect this graph? (lowers the

activation energy so faster reaction)

7 - Potential Energy Diagrams

 Draw an energy diagram:

Heat of reactants: 250 KJ

Heat of products: 25 KJ

Energy of activated complex: 350 KJ

Heat of reaction: _____ KJ

Activation Energy: ______ KJ

Exothermic/Endothermic?

How does a catalyst affect this graph?

7 - Potential Energy Diagrams

Answers

 Draw an energy diagram:

Heat of reactants: 250 KJ

Heat of products: 25 KJ

Energy of activated complex: 350 KJ

Heat of reaction: _____ KJ (25 – 250 = -225 KJ)

Activation Energy: ______ KJ (350 – 250 = 100 KJ)

Exothermic/Endothermic? EXOTHERMIC, energy of

products is LESS than reactants so excess energy given off!

How does a catalyst affect this graph? Again, catalyst lowers

the activation energy

8 - Collision Theory

 Identify 5 ways to increase the rate of a

reaction.

8 - Collision Theory Answers

 Identify 5 ways to increase the rate of a

reaction.

 Increase temp – more collisions

 Increase concentration of reactants –

more collisions

 Increase Pressure

 Decrease volume

 Add a catalyst

 Add a more reactive substance

9- Reaction Rate

 Calculate the rate of the reaction below.









Time (second)

9- Reaction Rate Answers

 Calculate the rate of the reaction below.









Rate = change in something/change in time



= (135 nm – 0 nm)/100 sec

= 1.35 nm/sec









Time (second)



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