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Millikan Oil Drop

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11/17/2011
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Millikan Oil Drop Question

American physicist

Robert Millikan won the

1923 Nobel Prize in

physics. conducted a

series of experiments

that measured the

electrical charge carried

by an electron.

Problem

 Two large parallel metal plates are

separated by a distance of 2.0 x 10-3

meters.

 The plates are attached to a 4.0 x 103 volt

source.

++++++++++





------ -----

Calculate

 The FIELD INTENSITY between the

plates ( E = V/d)

 Determine the FORCE on an electron in

the FIELD ( F = q E)

 Calculate the WORK necessary to move

an electron from the positive plate to the

negative plate in ELECTRON VOLTS and

in Joules ( W = q V)

++++++++++

Sample Solutions

Field intensity

------ -----

Two large parallel metal plates are

separated by a distance of 2.0 x 10-3 m.

The plates are attached to a 4.0 x 10 3 V

 E=V/d

= (4.0 x 10 3 V) / ( 2.0 x 10-3 m)

= 2.0 x 10 6 V/m

Force Example

Calculate the force exerted on an electron

on an electric field, whose intensity is

2.0 x 10 –19 C

F =qE

= ( 1.6 x 10 –19 C ) (2.0 x 10 3 N/C)

= 3.2 x 10 –16 N

Work Example

Calculate the work necessary to move an

electron from the positive plate to the

negative plate in eV and in J.

 W = qV

= 1 electron x (4.0 x 10 3 V)

= 4.0 x 10 3 eV

Since : 1 eV = 1.6 x 10 –19 J

W = 1 electron x (4.0 x 10 3 V)

= (1.6 x 10 –19 J/ev)(4.0 x 10 3 eV)

= 6.4 x 10 –16 J

Summary

 Robert Millikan conducted a

series of experiments that

measured the electrical

charge carried by an electron.

 Using the potential ( volts )

formulas based on an

electron „s “pressure”

 Solve for FIELD

INTENSITY, FORCE, and

WORK on the electron.



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