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NUMBER THEORY

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MGF1106

Unit Two

Ex. 4.1 Number Theory

Objectives 18-20

Ex. 4.1



Objective 18



To write numbers in

prime factored form

Natural numbers greater than one can be

prime composite

classified as either ________ or _________.



Prime

_______ numbers are those natural greater

than 1 whose only factors are 1 and the

number.



Composite

___________ numbers are those natural

numbers greater than one that have factors

other than 1 and the number.

factor

A ________ is a multiplier.

The prime factorization of a number is when

the number has been written as a product of

prime numbers.

Write 540 in prime factored form.

540

22 ×33 × 5

10 54

2 5 6 9

2 3 3 3

Ex. 4.1



Objective 19



To find the number of

factors of a number

If n = paqbrc where p, q, and r are prime

numbers and a, b, and c are the number of

times each prime occurs in the number, the

the number of factors of n is found by

(a+1)(b+1)(c+1)

finding the product __________________.



Find the number of factors of 24 · 32.



(4+1)(2+1) = 5(3) = 15

Find the number of factors of 600.

Step 1: Write the number in prime factored

form.

600



10 60

2 5 6 10

2 3 2 5



23 ×31 × 52

600 = 23 ×31 × 52



Step 2: Find the number of factors.



(3+1)(1+1)(2+1) = 4(2)(3) = 24

Ex. 4.1



Objective 20



To find the sum of the

factors of a number

Find the sum of the factors of 24.

The sum of the factors of a number can be

found by using the prime factored form of the

number.

24  2  3

3 1



To do this, use the prime factors themselves.

Write the powers of each of the prime factors

beginning with 0 and going to the power of the

factor in the prime factored form.

0 1 2 3 0 1

2 ,2 ,2 ,2 3 ,3

The sum of these are formed for each of the

prime factors and then the product of these

sums in found.





(2  2  2  2 )(3  3 )

0 1 2 3 0 1





(1  2  4  8)(1  3)

(15)( 4)

60

Looking at this prime factored form of 600

which is 23 ×31 × 52, we would find the sum

by:







(20 + 21 + 22 + 23)(30 + 31)(50 + 51 + 52)



(1 + 2 + 4 + 8)(1 + 3)(1 + 5 + 25)

(15)(4)(31) = 1860

Find the sum of the factors of 31 · 23.

(30 + 31)(20 + 21 + 22 + 23)

(1 + 3)(1 + 2 + 4 + 8)

4(15) = 60



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