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Chapter 3 DC to DC CONVERTER (CHOPPER)

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Chapter 3



DC to DC CONVERTER

(CHOPPER)

• General

• Buck converter

• Boost converter

• Buck-Boost converter

• Switched-mode power supply

• Bridge converter

• Notes on electromagnetic compatibility

(EMC) and solutions.









Power Electronics and 1

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

DC-DC Converter

(Chopper)

DEFINITION:

Converting the unregulated DC input to a

controlled DC output with a desired

voltage level.



• General block diagram:





DC supply

(from rectifier-

DC output LOAD

filter, battery,

fuel cell etc.)





Vcontrol

(derived from

feedback circuit)









• APPLICATIONS:

– Switched-mode power supply (SMPS), DC

motor control, battery chargers

Linear regulator

• Transistor is operated

in linear (active)

mode. + VCEce  IL



+

• Output voltage Vin

RL Vo









Vo  Vin  Vce

LINEAR REGULATOR



• The transistor can be

conveniently + Vce 

IL

modelled by an

RT

equivalent variable +

RL Vo

resistor, as shown. Vin







• Power loss is high at

EQUIVALENT

high current due to: CIRCUIT



Po  I L 2  RT

or

Po  Vce  I L

Power Electronics and 3

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Switching Regulator



• Transistor is operated

in switched-mode:

+ Vce  IL

– Switch closed:

Fully on (saturated) +

– Switch opened: Vin

RL

Vo

Fully off (cut-off)





SWITCHING REGULATOR

– When switch is open,

no current flow in it IL

– When switch is

closed no voltage SWITCH

+

drop across it. Vin

RL Vo





• Since P=V.I, no losses

occurs in the switch.

– Power is 100% EQUIVALENT CIRCUIT

transferred from Vo

source to load. Vin

– Power loss is zero

(ON) (OFF) (ON)

(for ideal switch): closed open closed



DT T



• Switching regulator is OUTPUT VOLTAGE

the basis of all DC-DC

converters



Power Electronics and 4

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Buck (step-down) converter



S L



+

Vd D C RL

Vo







CIRCUIT OF BUCK CONVERTER

iL

S + vL 

+

Vd D RL Vo









CIRCUIT WHEN SWITCH IS CLOSED



S iL



+ vL 

+

Vd RL Vo

D







CIRCUIT WHEN SWITCH IS OPENED





Power Electronics and 5

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Switch is turned on (closed)

• Diode is reversed + vL -

biased.

S iL +

+

C Vo

• Switch conducts Vd VD RL

 

inductor current



vL

• This results in

positive inductor VdVo

voltage, i.e: opened opened

closed closed



t

v L  Vd  Vo



• It causes linear Vo

increase in the iL

inductor current

iLmax

di IL

vL  L L iLmin

dt

1

 iL   v L dt DT T

t

L

Power Electronics and 6

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Switch turned off (opened)



+ vL -

• Because of inductive

energy storage, i L S iL +

continues to flow. Vd C RL Vo

D



• Diode is forward

biased vL



VdVo

• Current now flows opened opened

(freewheeling) closed closed



through the diode. t







• The inductor voltage

can be derived as: Vo

iL





vL  Vo iLmax

IL

iLmin



(1-D)T

t

DT T







Power Electronics and 7

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Analysis

When the switch is closed (on) :

di

v L  Vd  Vo  L L vL

dt

di V  Vo Vd Vo

 L d closed

dt L t

Derivative of iL is a positive

constant.Therefore iL must

increased linearly. iL



From Figure iL max

diL iL iL Vd  Vo

   IL iL

dt t DT L

 V  Vo 

 iL closed   d

iL min

  DT

 L  t

DT T

For switch opened,

di

v L  Vo  L L

dt

di  Vo

 L

dt L

di i i L  Vo

 L L 

dt t (1  D )T L

 V 

 iL opened   o   (1  D )T

 L 

Power Electronics and 8

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Steady-state operation



iL

Unstable current



t



iL Decaying current





t



iL Steady-state current





t



Steady - state operation requires that iL at the

end of switching cycle is the same at the

begining of the next cycle. That is the change

of iL over one period is zero, i.e :

iL closed  iL opened  0

 Vd  Vo   V 

   DTs   o   (1  D)Ts  0

 L   L 

 Vo  DVd

Power Electronics and 9

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Average, Maximum and

Minimum Inductor Current

iL





Imax

IL iL



Imin



t



Average inductor current  Average current in R L

V

 IL  IR  o

R

Maximum current :

iL Vo 1  Vo 

I max  I L     (1  D)T 

2 R 2 L 

 1 (1  D) 

 Vo   

 R 2 Lf 

Minimum current :

iL  1 (1  D) 

I min  I L   Vo   

2 R 2 Lf 

Inductorcurrent ripple :

iL  I max  I min

Power Electronics and 10

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Continuous Current Mode (CCM)

iL



Imax









Imin t

0







From previous analysis,

iL  1 (1  D) 

I min  I L   Vo   

2 R 2 Lf 

For continuous operation, I min  0,

 1 (1  D) 

Vo   0

R 2 Lf 

(1  D)

 L  Lmin  R

2f

This is the minimum inductor current to

ensure continous mode of operation.

Normally L is chosen b be  Lmin



Power Electronics and 11

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Output voltage ripple

KCL, Capacitor current :

ic  iL  iR L iL iR



The charge can be witten as : +

iC

Q  CVo Vo



 Q  CV 



Q

 o Vo 

C imax

iL

Use triangle area formula :

iL=IR

1  T  i 

Q    L  Vo/R imin

2  2  2 

0

TiL iC



8

Ripple voltage (Peak - to peak)

0



TiL (1  D)

 Vo  

8C 8 LCf 2

So, the ripple factor,

V (1  D)

r o 

Vo 8 LCf 2

Note : Ripple can be reduced by :

1) Increasing switching frequency

2) Increasing inductor size

3) Increasing capacitor size.

Power Electronics and 12

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Basic design procedures

SWITCH L



Lmin= ?

RL

L = 10Lmin

Vd Po = ?

f=? D

(input C Io = ?

D=? ripple ?

spec.)

TYPE ?









• Calculate D to obtain required output voltage.



• Select a particular switching frequency (f) and device

– preferably f>20KHz for negligible acoustic noise

– higher fs results in smaller L and C. But results in higher losses.

Reduced efficiency, larger heat sink.

– Possible devices: MOSFET, IGBT and BJT. Low power MOSFET can

reach MHz range.

• Calculate Lmin. Choose L>>10 Lmin

• Calculate C for ripple factor requirement.

– Capacitor ratings:

• must withstand peak output voltage

• must carry required RMS current. Note RMS current for

triangular w/f is Ip /3, where Ip is the peak capacitor current given

by iL/2.

• ECAPs can be used



• Wire size consideration:

– Normally rated in RMS. But iL is known as peak. RMS value

for iL is given as:

2

2 i 2 

I L, RMS  I L   L 

 3 



Power Electronics and 13

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Examples

• A buck converter is supplied from a 50V battery source. Given

L=400uH, C=100uF, R=20 Ohm, f=20KHz and D=0.4.

Calculate: (a) output voltage (b) maximum and minimum

inductor current, (c) output voltage ripple.



• A buck converter has an input voltage of 50V and output of

25V. The switching frequency is 10KHz. The power output is

125W. (a) Determine the duty cycle, (b) value of L to limit the

peak inductor current to 6.25A, (c) value of capacitance to limit

the output voltage ripple factor to 0.5%.



• Design a buck converter such that the output voltage is 28V

when the input is 48V. The load is 8Ohm. Design the converter

such that it will be in continuous current mode. The output

voltage ripple must not be more than 0.5%. Specify the

frequency and the values of each component. Suggest the power

switch also.









Power Electronics and 14

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Boost (step-up) converter

L D









Vd C +

S

RL Vo





CIRCUIT OF BOOST CONVERTER

iL L D

+ vL 



Vd +

S C

RL Vo







CIRCUIT WHEN SWITCH IS CLOSED

L

D

+ vL -

+

Vd C RL

S Vo







CIRCUIT WHEN SWITCH IS OPENED







Power Electronics and 15

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Boost analysis:switch closed

iL

L D

+ vL 

+

Vd C vo

S











v L  Vd Vd





di

L L v L

CLOSED

dt

t

diL Vd

  V d V o

dt L

diL iL iL

  i iL

t DT

L



dt

di V

 L  d

dt L DT T t



Vd DT

iL closed 

L

Power Electronics and 16

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Switch opened

iL

D

+ vL -

+

Vd C vo

S

-









v L  Vd  Vo

diL

L Vd

dt

di V  Vo vL

 L d OPENED



dt L t



diL iL V d V o



dt t

iL iL

 iL

(1  D)T

( 1-D )T

t

diL Vd  Vo

DT T



 

dt L

Vd  Vo (1  DT )

 iL opened 

L

Power Electronics and 17

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Steady-state operation



iL closed  iL opened  0

Vd DT Vd  Vo (1  D )T

 0

L L

Vd

 Vo 

1 D



• Boost converter produces output voltage that is

greater or equal to the input voltage.

• Alternative explanation:

– when switch is closed, diode is reversed. Thus

output is isolated. The input supplies energy to

inductor.

– When switch is opened, the output stage

receives energy from the input as well as from

the inductor. Hence output is large.

– Output voltage is maintained constant by

virtue of large C.







Power Electronics and 18

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Average, Maximum, Minimum

Inductor Current



Input power  Output power

Vo 2

Vd I d 

R

2

 Vd 

 

(1  D)  Vd 2

Vd I L   

R (1  D) 2 R

Average inductor current :

Vd

 IL 

(1  D) 2 R

Maximum inductor current :

iL Vd V DT

 I max  I L    d

2 (1  D) 2 R 2L

Minimum inductor current :

iL Vd V DT

 I min  I L    d

2 (1  D) 2 R 2L



Power Electronics and 19

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

L and C values



For CCM,

I min  0 Vd

vL

Vd V DT

2

 d 0

(1  D) R 2L

D1  D 2 TR

Lmin  VdVo

2 Imax



D1  D 2 R

iL

 Imin

2f



Ripple factor iD Imax



V 

Q   o  DT  CVo

Imin



R

Io=Vo / R

Vo DT Vo D

Vo  

RCf RCf ic



V D

r o 

Vo RCf

Q



DT T

Power Electronics and 20

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Examples

• The boost converter has the following parameters: V d=20V,

D=0.6, R=12.5ohm, L=65uH, C=200uF, fs=40KHz. Determine

(a) output voltage, (b) average, maximum and minimum

inductor current, (c) output voltage ripple.



• Design a boost converter to provide an output voltage of 36V

from a 24V source. The load is 50W. The voltage ripple factor

must be less than 0.5%. Specify the duty cycle ratio, switching

frequency, inductor and capacitor size, and power device.









Power Electronics and 21

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Buck-Boost converter



S

D

+



Vd C

L RL Vo



RL





CIRCUIT OF BUCK-BOOST CONVERTER





S D

+ +



Vd iL vL Vo

 







CIRCUIT WHEN SWITCH IS CLOSED



S D

+ +

Vd iL vL

Vo







CIRCUIT WHEN SWITCH IS OPENED







Power Electronics and 22

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Buck-boost analysis

Vd

Switch closed vL

di

v L  Vd  L L

dt

diL Vd VdVo

 

dt L Imax



iL iL Vd iL

  Imin

t DT L

V DT

 (iL ) closed  d Imax

L iD

Switch opened Imin



di

v L  Vo  L L Io=Vo / R

dt

di V

 L o i c

dt L

iL iL Vo Q

 

t (1  D )T L DT T

Vo (1  D )T

 (iL ) opened 

L

Power Electronics and 23

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Output voltage

Steady state operation :

 iL(closed )   iL(opened )  0

Vd DT Vo (1  D)T

  0

L L

Output voltage :

 D 

 Vo  Vs  

1  D 



• NOTE: Output of a buck-boost converter either be

higher or lower than input.

– If D>0.5, output is higher than input

– If D<0.5, output is lower input



• Output voltage is always negative.



• Note that output is never directly connected to load.



• Energy is stored in inductor when switch is closed

and transferred to load when switch is opened.



Power Electronics and 24

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Average inductor current





Assuming no power loss in the converter,

power absorbed by the load must equal

power supplied the by source, i.e.

Po  Ps

Vo2

 Vd I s

R

But average source current is related to

average inductor current as :

Is  ILD

Vo2

  Vd I L D

R

Substituting for Vo ,

Vo2 Po Vd D

 IL   

Vd RD Vd D R (1  D ) 2





Power Electronics and 25

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

L and C values

Max and min inductor current,

iL Vd D Vd DT

 I max  I L   2



2 R (1  D ) 2L

iL Vd D V DT

 I min  I L    d

2 R (1  D ) 2 2L

For CCM

Vd D V DT

2

 d 0

R (1  D ) 2L

(1  D ) 2 R

 Lmin 

2f

Output voltage ripple,

 Vo 

Q    DT  CVo

R

Vo DT Vo D

Vo  

RC RCf

V D

r o 

Vo RCf

Power Electronics and 26

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Converters in CCM: Summary

Buck

Vo

S L D

V + Vd

D C RL

Vo Vo 1  D



d



 Vo 8 LCf 2

(1  D ) R

Lmin 

2f



L Boost

D

Vo 1



V + Vd 1  D

C Vo

S Vo D



d

RL  Vo RCf

D (1  D ) 2 R

Lmin 

2f



S Buck  Boost

Vo D

D + 

V C Vo

Vd 1 D

L RL

d

 Vo D



Vo RCf

(1  D) 2 R

Lmin 

2f

Power Electronics and 27

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Control of DC-DC converter:

pulse width modulation (PWM)





Vo (desired)

+ Vcontrol Switch control

signal

Vo (actual) Comparator

-

Sawtooth

Waveform Sawtooth

Waveform





Vcontrol 1

Vcontrol 2









Switch

control

ton 2 signal





ton 1

T









Power Electronics and 28

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Isolated DC-DC Converter

• Isolated DC-DC requires isolation transformer

• Two types: Linear and Switched-mode



• Advantages of switched mode over linear power

supply

-Efficient (70-95%)

-Weight and size reduction



• Disadvantages

-Complex design

-EMI problems



• However above certain ratings,

SMPS is the only feasible choice



• Types of SMPS

-Flyback

-forward

-Push-pull

-Bridge (half and full)







Power Electronics and 29

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Linear and SMPS block diagram

Basic Block diagram of linear power supply

C E

Vce=Vd-Vo +Vo DC Regulated

DC Unregulated

B +

+

Base/gate RL

Vd Drive Vo

Line

Input -

1 / 3 -

Rectifier/ Error Vo

50/60 Hz Filter Amp.

Isolation

Transformer

Vref









Basic Block diagram of SMPS

DC-DC CONVERSITION AND

DC ISOLATION

DC

Unregulated Regulated

High

RECTIFIER Frequency

EMI

AND

FILTER rectifier Vo

FILTER

and

filter

Vref



Base/

PWM error

gate

Controller Amp

drive





Power Electronics and 30

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

High frequency transformer

Basic function :

1) Input - output electrical isolation

2) step up/down time - varying voltage

Basic input - output relationship

v1 N1

 ;

v2 N 2

i1 N 2



i2 N1

Models :

i1 N1 N2 i2

+ +

V1 V2 Ideal model

 



i1 N1 N2 i2

+ +

Lm Model used for

V1 V2



most PE application











Power Electronics and 31

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Flyback Converter



+

C R Vo

Vd LM











Flyback converter circuit







iD

iS i1 N1 N2

+

+  + vD 

iLM v2 iC iR Vo

v1

Vd

 + 

+ vSW  i2







Model with magnetising

inductance









Power Electronics and 32

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Operation: switch closed

0 N1 N2

is=iLM

 +

+

iLM v2

v1 Vo

Vd +

 

v1=Vs 0





diLm

v1  Vd  Lm

dt

diLm iLm iLm Vd

  

dt dt DT Lm





 iLm

closed

 

Vd DT

Lm

On the load side of the transformer,

 N2   N2 

 N   Vd  N 

v2  v1    

 1  1

N 

v D  Vo  Vd  2   0, i.e. diode turned off

N 

 1

Therefore,

i2  0 and i1  0

Power Electronics and 33

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Switch opened

iD

N1 N2

+ +



iLM v1 v2= VS Vo

Vs  + 

+ vSW 





N 

v1  Vo  1 

N 

 2

But v2  Vo

N  N 

 v1  v2  1   Vo  1 

N  N 

 2  2

di N 

v1  Lm L m  Vo  1 

N 

dt  2

diL m iL m iL m  Vo  N1 

   N 



dt dt 1  D T Lm  2  

V (1  D )T  N1 

 iL m open   o 

N  

Lm  2

Voltage across the switch :

N 

vSW  Vd  Vo  1 

N 

 2

Power Electronics and 34

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Output voltage



For steady - state operation,

iL closed  iL opened  0

m m



Vd DT Vo 1  D T  N1 

  

N 0



Lm Lm  2

 D  N 2 

 Vo  Vd  N 

 

 1  D  1 



• Input output relationship is similar to buck-boost

converter.



• Output can be greater of less than input,depending

upon D.



• Additional term, i.e. transformer ratio is present.









Power Electronics and 35

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Flyback waveforms



Ps  P0 Vs



V0 2 v1

Vd I s 

R

I s is related to I Lm as : -V(N1 /N2)







Is 

I Lm DT

T

 

 I Lm D

iLm

iLM





Solving for I Lm

is



 

Vd I Lm D 

V02

R

t

2

V0

 I Lm 

Vd DR iD



I Lm can written as :

2 iC

Vd D  N2 

I Lm  

2 N 



(1  D ) R  1 

Vo/ R

V0  N 2 

DT T t

 

N 

(1  D ) R  1 





Power Electronics and 36

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Max, Min inductor current

iLm

I Lm  I Lm 

,max 2

2

Vd D  N 2  V d DT

 

2 N 

 

(1  D ) R  1  2 Lm

iLm

I Lm ,min  I Lm 

2

2

Vd D  N 2  Vd DT

 

2 N 

 

(1  D ) R  1  2 Lm

For CCM, I Lm , min  0

2

Vd D  N2  Vd DT Vd D



2 N 

  

(1  D ) R  1  2 Lm 2 Lm f

2

V (1  D) R  N1  2

  Lm min  d 

N  

2f  2

Ripple calculatio n is similar to boost,

V0 D

r 

V0 RCf

Power Electronics and 37

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Example

The Flyback converter has these specifications:

DC input voltage: 40V

Output voltage: 25V

Duty cycle: 0.5

Rated load: 62.5W

Max peak-peak inductor current ripple:

25% of the average inductor current.

Maximum peak-peak output voltage: 0.1V

Switching frequency: 75kHz



Based on the abovementioned specifications, determine

a) Transformer turns ratio

b) Value of magnetizing inductor Lm.

c) Maximum and minimum inductor current.

d) Value of capacitor C.









Power Electronics and 38

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Full-bridge converter



SW1 SW3

Lx

+ + +

NS vx Vo

C R

 

vp

VS

NS





SW4 SW2





SW1,SW2





DT T

SW3,SW4





T T

 DT

VP 2 2

VS









-VS

Vx

N 

VS  S 

N 

 P





DT T T T

 DT

2 2



Power Electronics and 39

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB

Full bridge: basic operation

• Switch “pair”: [S1 & S2];[S3 & S4].



• Each switch pair turn on at a time as shown. The

other pair is off.



• “AC voltage” is developed across the primary.

Then transferred to secondary via high frequency

transformers.



• On secondary side, diode pair is “high frequency

full wave rectification”.



• The choke (L) and (C ) acts like the “buck

converter” circuit.



• Output Voltage





 Ns 

Vo  2Vs   D

Np 

 





Power Electronics and 40

Drives (Version 3-2003)

Dr. Zainal Salam, UTM-JB


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